WebMay 27, 2024 · Approach: Let a is the first term and d is the common difference of the given AP. Therefore mth term = a + (m-1)d and nth term = a + (n-1)d From these two equations, find the value of a and d. Now use the formula of sum of p terms of an AP. Sum of p terms = ( p * ( 2*a + (p-1) * d ) ) / 2; Below is the implementation of the above approach: C++ Java WebDec 9, 2014 · If the sum of first m terms of an A.P. is n and the sum of first n terms is m, then show that the sum of its first (m + n) terms is - (m + n). Asked by d7016880266 20 Jan, 2024, 08:14: PM ANSWERED BY EXPERT CBSE 10 - Maths maths doubt Asked by dixitayush414 04 Jan, 2024, 09:03: PM ANSWERED BY EXPERT CBSE 10 - Maths
Finding first term and common difference when sum is given
WebMar 30, 2024 · We know that Sn = n/2 ( 2a + (n 1)d ) Where, Sn = sum of n terms of A.P. n = number of terms a = first term and d = common difference Thus, Sum of n terms = Sn = /2 (2a + (n 1)d) And Sum of m terms = Sm = /2 (2a + (m 1)d) It is given that, ratio of the sums of m and n terms of an A.P. is m2: n2 (Sum of m terms )/ (Sum of n terms) = m2/n2 (Sm )/ … WebConsider an arithmetic progression (AP) whose first term is a 1 (or) a and the common difference is d.. The sum of first n terms of an arithmetic progression when the n th term … grand gin rummy app
Arithmetic Progression - AP Formula, nth Term, Sum, Examples
WebAug 29, 2024 · In an AP the sum of first n terms is 3n^2/2 + 5n/2 find the 25th term. Advertisement Expert-Verified Answer 1282 people found it helpful Brainly User Let the sum of n terms be given by Sn so Sn = 3n²/2+ 5n/2 S1 = 3 (1)²/2 + 5 (1)/2 = 3/2+5/2 => 4 so 1st term is 4 say 'a' Now S2 = 3 (2)²/2 + 5 (2)/2 = 6+5 => 11 Now a2 = S2 - a1 => a2 = 11-4 = 7 WebApr 7, 2024 · If the sum and product of first 3 terms of a decreasing AP are 54 and 5760 respectively, then the maximum possible value of sum of first n terms (n∈N) is (Sn)max= … WebMar 27, 2024 · Solution For 10] Find the sum of first ' n ' terms of an AP 2 ,8 ,18 ,32 , 11] If α,β and γ are the zeroes of the polynomial P(x)=x3−6x2−x+30 then fin. The world’s only live … chinese delivery in west des moines iowa